document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1112389>Question 1112389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the formula <BR>\n" );
document.write( "C(n, x)pxqn &#8722; x<BR>\n" );
document.write( "to determine the probability of the given event. (Round your answer to four decimal places.)<BR>\n" );
document.write( "The probability of at least three successes in six trials of a binomial experiment in which <BR>\n" );
document.write( "p = 1/2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #727411 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=727411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do 0, 1, 2 successes and subtract the combined sum from 1<BR>\n" );
document.write( "For 0, it is .5^6=0.0156<BR>\n" );
document.write( "For 1 it is 6C1(1/2)^6, which is 6 times the first or 0.0938<BR>\n" );
document.write( "For 2 it is 6C2(1/2)^6, which is 15 times the first or 0.2344<BR>\n" );
document.write( "The sum of those 3 is 0.3438\r<BR>\n" );
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document.write( "The probability is for at least 3 successes, so that is 1-0.3438 or 0.6562 </SPAN>\n" );
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