document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1112372>Question 1112372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular paper has a width of 1 2/3 meters and an area of 4 7/12 meters square?If you want to put a decorative border around the paper with 8 3/4 meters of material,do you have enough material?Explain. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #727409 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=727409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length*width=area<BR>\n" );
document.write( "l*(5/3)=55/12 m^2<BR>\n" );
document.write( "l=55/12 divided by 5/3 or 55/12*3/5<BR>\n" );
document.write( "l=11/4 or 2.75m<BR>\n" );
document.write( "half perimeter is the sum of 5/3 and 11/4, with common denominator of 12, it is (20+33)/12=53/12<BR>\n" );
document.write( "Full perimeter is twice that or 53/6 m.  This is 8 5/6 meters, which is more than 8 3/4 meters of material, so the answer is no, not enough material. </SPAN>\n" );
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