document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99931>Question 99931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a coffee shop decides to blend a coffee that sells for$12 per pound with a coffee that sells for $9 per pound to produce a blend that will sell for $10 per pound. how much of each should be used to yield 20 pounds of the new blend? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72736 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12x+9(20-x)=10*20<BR>\n" );
document.write( "12x+180-9x=200<BR>\n" );
document.write( "3x=200-180<BR>\n" );
document.write( "3x=20<BR>\n" );
document.write( "x=20/3 pounds of $12 coffee is needed.<BR>\n" );
document.write( "20-6 2/3=13 1/3 or 40/3 pounds of $9 coffee is needed.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "12*20/3+9*40/3=200 <BR>\n" );
document.write( "240/3+360/3=200<BR>\n" );
document.write( "80+120=200<BR>\n" );
document.write( "200=200 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );