document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1112147>Question 1112147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let S be the event that a randomly selected college student has taken a statistics course, and let C be the event that the same student has taken a chemistry course. Suppose P(S) = 0.35, P(C) = 0.26, and P(S &#8745; C) = 0.16 <BR>\n" );
document.write( "Find the probability that a student has taken neither statistics nor chemistry. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #727200 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=727200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Let S be the event that a randomly selected college student has taken a statistics course, and let C be the event that the same student has taken a chemistry course. Suppose P(S) = 0.35, P(C) = 0.26, and P(S &#8745; C) = 0.16 <BR>\n" );
document.write( "Find the probability that a student has taken neither statistics nor chemistry.<BR>\n" );
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document.write( "Note:: (S OR C)' = S' AND C'<BR>\n" );
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document.write( "S' AND C' = S' + C' - (S' OR C') = S'+C'- (S AND C)' = 0.65+0.74-0.84 = 0.55<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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