document.write( "Question 1111985: The temperature of a patient during an illness is given by the function below, where T is the temperature, in degrees Fahrenheit, at time t, in days, after the onset of the illness. Graph the function using a graphing calculator and use the MAXIMUM feature to find at what time the patient's temperature was highest. What was the highest temperature?
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document.write( "T(t)=0.7tsquared +4.2t+98.6, 0 less than or equal too t less than or equal to 6 \n" );
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Algebra.Com's Answer #727141 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the function you provided is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "T(t) = .7 * t^2 + 4.2 * t + 98.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it will not give you a maximum temperature.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is because the coefficient of the t^2 term is positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in order for the function to give you a maximum temperature, the coefficint of the t^2 term has to be negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to graph this function:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let x = t and let y = T(t).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the function becomes y = .7 * x^2 + 4.2 * x + 98.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the domain is 0 <= x <= 6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's the graph of the function as given.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can see that there is no maximum.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there is only a minimum.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here is the graph of the function when the coefficient of the x^2 term is negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( "now you have a maximum.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from the graph, you can see that, when x = 0, the temperature is 98.6, and when x = 3, the temperature is 104.9, and when x = 6, the temperature is 98.6 again.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the maximum temperature is when x = 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the maximum temperature is 104.9 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we allowed y to be equal to T(t) and we allowed x to be equal to t in order for the graphing software to be able to handle the function.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "some graphing functions can handle it the way it was originally written, but a lot can't, which is why we made the equivalency.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "bottom line:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "coefficient of the x^2 term, or the t^2 term, needs to be negative in order to get a maximum out of this quadratic function.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the quadratic equation is in standard form, you could also find the maximum vaalue by using the formula:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -b/2a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the standard form of a quadratic equation is y = ax^2 + bx+ c, when y is equal to 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in this form:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = the coefficient of the x^2 term. \n" ); document.write( "b = the coefficient of the x term. \n" ); document.write( "c = the constant term.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation of y = -.7 * x^2 + 4.2 * x + 98.6 gets you:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = -.7 \n" ); document.write( "b = 4.2 \n" ); document.write( "c = 98.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -b/2a becomes x = -4.2 / -1.4 which gets you x = 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 3, y = -.7 * 3^2 + 4.2 * 3 + 98.6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this results in y = 104.9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this agrees with what the graph is telling you, as it should.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |