document.write( "Question 1112092: one grade of tea, worth $3.90 per pound is to be mixed with another grade worth $2 per pound to make 30 pounds that will sell $2.76 per pound how much of each grade of tea must be used \n" ); document.write( "

Algebra.Com's Answer #727108 by mananth(16946) $\"\"$ $\"About$

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component Price $ ---------------- quantity
\n" ); document.write( "Grade I tea 3.9 ---------------- x lb
\n" ); document.write( "Grade II tea 2 ---------------- 30 - x lb
\n" ); document.write( "Mixture 2.76% ---------------- 30
\n" ); document.write( "
\n" ); document.write( "3.9 x + 2 ( 30 - x ) = 30.00 * 2.76
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\n" ); document.write( "3.9 x + 60 - 2 x = 82.80
\n" ); document.write( "3.9 x - 2 x = 82.8 - 60
\n" ); document.write( "1.9 x = 22.8
\n" ); document.write( "/ 1.9
\n" ); document.write( " x = 12 lb $3.90 Grade I tea
\n" ); document.write( " 18 lb $2.00 Grade II tea
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