document.write( "Question 1112053: Problem Page The area of a rectangle is 65ft^2 and the length of the rectangle is 3ft less than twice the width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #727079 by stanbon(75887)\"\" \"About 
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Problem Page The area of a rectangle is 65ft^2 and the length of the rectangle is 3ft less than twice the width. Find the dimensions of the rectangle.
\n" ); document.write( "Width = W
\n" ); document.write( "Length = 2W-3
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\n" ); document.write( "Equation:
\n" ); document.write( "W(2W-3) = 65
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\n" ); document.write( "2W^2 - 3W - 65 = 0
\n" ); document.write( "W = [3+-sqrt(9-4*2*-65)]/4
\n" ); document.write( "W = [3+-sqrt(529)]/4
\n" ); document.write( "positive solution:
\n" ); document.write( "W = 6.5 ft (width)
\n" ); document.write( "2W-3 = 10 ft (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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