document.write( "Question 1112053: Problem Page The area of a rectangle is 65ft^2 and the length of the rectangle is 3ft less than twice the width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #727076 by ikleyn(52932)\"\" \"About 
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document.write( "W*L = 65\r\n" );
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document.write( "W*(2W-3) = 65\r\n" );
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document.write( "2W^ - 3W - 65 = 0\r\n" );
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document.write( "\"W%5B1%2C2%5D\" = \"%283+%2B-+%28sqrt%289+-+4%2A2%2A%28-65%29%29%29%29%2F%282%2A2%29\" = \"%283+%2B-+23%29%2F4\".\r\n" );
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document.write( "Answer.  The width is  W = \"%283+%2B+23%29%2F4\" = 6.5ft.\r\n" );
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document.write( "         The length is  L = 2W - 3 = 10 ft.\r\n" );
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document.write( "Check.  10*6.5  = 65.   ! Correct !\r\n" );
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