document.write( "Question 99881: hi I do not undrestand solving using substitution method for example
\n" ); document.write( "x=y-1 x=y+6 r=-3s
\n" ); document.write( "y=4-2x y=-2-x r=10-4s\r
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Algebra.Com's Answer #72704 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
x=y-1 now substitute (y-1) for x in the other equation & solve for y:
\n" ); document.write( "y=4-2(y-1)
\n" ); document.write( "y=4-2y+1
\n" ); document.write( "y+2y=5
\n" ); document.write( "3y=5
\n" ); document.write( "y=5/3 answer.
\n" ); document.write( "now replace y with 5/3 & solve for x:
\n" ); document.write( "x=5/3-1
\n" ); document.write( "x=5/3-3/3
\n" ); document.write( "x=2/3 answer.
\n" ); document.write( "-------------------------------------------------
\n" ); document.write( "x=y+6 now replace x in the othere equation & solve for y:
\n" ); document.write( "y=2-(y+6)
\n" ); document.write( "y=2-y-6
\n" ); document.write( "y+y=-4
\n" ); document.write( "2y=-4
\n" ); document.write( "y=-4/2
\n" ); document.write( "y=-2 answer.
\n" ); document.write( "x=-2+6
\n" ); document.write( "x=4 answer.
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\n" ); document.write( "Now do the same with the next set of equations:
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