document.write( "Question 99881: hi I do not undrestand solving using substitution method for example
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document.write( "x=y-1 x=y+6 r=-3s
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document.write( "y=4-2x y=-2-x r=10-4s\r
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Algebra.Com's Answer #72704 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! x=y-1 now substitute (y-1) for x in the other equation & solve for y: \n" ); document.write( "y=4-2(y-1) \n" ); document.write( "y=4-2y+1 \n" ); document.write( "y+2y=5 \n" ); document.write( "3y=5 \n" ); document.write( "y=5/3 answer. \n" ); document.write( "now replace y with 5/3 & solve for x: \n" ); document.write( "x=5/3-1 \n" ); document.write( "x=5/3-3/3 \n" ); document.write( "x=2/3 answer. \n" ); document.write( "------------------------------------------------- \n" ); document.write( "x=y+6 now replace x in the othere equation & solve for y: \n" ); document.write( "y=2-(y+6) \n" ); document.write( "y=2-y-6 \n" ); document.write( "y+y=-4 \n" ); document.write( "2y=-4 \n" ); document.write( "y=-4/2 \n" ); document.write( "y=-2 answer. \n" ); document.write( "x=-2+6 \n" ); document.write( "x=4 answer. \n" ); document.write( "-------------------------------------------------------- \n" ); document.write( "Now do the same with the next set of equations: \n" ); document.write( " |