document.write( "Question 1112015: if 15% of the people in a certain factory are members of a union, find the probability that in a random sample of 200, fewer than 24 people are union members. First show the 3 conditions of the normal, find the probability and the show the diagram and what was plugged into the calculator\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #727039 by rothauserc(4718) $\"\"$ $\"About$

You can put this solution on YOUR website!
mean of the proportion is 0.15
\n" ); document.write( ":
\n" ); document.write( "1 - 0.15 = 0.85
\n" ); document.write( ":
\n" ); document.write( "standard error of the sample = square root(0.15 * 0.85 / 200) = 0.0252
\n" ); document.write( ":
\n" ); document.write( "sample size(200) > 30, we can use the normal distribution
\n" ); document.write( ":
\n" ); document.write( "24/200 = 0.12
\n" ); document.write( ":
\n" ); document.write( "z-score = (0.12 - 0.15) / 0.0252 = −1.19
\n" ); document.write( ":
\n" ); document.write( "Probability ( X < 24 ) = 0.1170
\n" ); document.write( ":
\n" ); document.write( " \n" ); document.write( "

\n" );