document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111973>Question 1111973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists leave towns 240 km apart at the same time and travel toward each other. One cyclist travels 4km/h faster than the other. If they meet in 5 hours, what is the rate of each cyclist?\r<BR>\n" );
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document.write( "Rate of fast cyclist:_____<BR>\n" );
document.write( "Rate of slow cyclist:_____ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726975 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726975\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two cyclists leave towns 240 km apart at the same time and travel toward each other. One cyclist travels 4km/h faster than the other. If they meet in 5 hours, what is the rate of each cyclist?\r<BR>\n" );
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document.write( "Distance = 240 km<BR>\n" );
document.write( "slow cyclist speed = x<BR>\n" );
document.write( "fast cyclist speed = (x+4)<BR>\n" );
document.write( "travel toward each\r<BR>\n" );
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document.write( "add up speed<BR>\n" );
document.write( "= x+x+4  -> 2x+4\r<BR>\n" );
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document.write( "t= d/s\r<BR>\n" );
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document.write( "5 =240/(2x+4)<BR>\n" );
document.write( "5(2x+4)=240<BR>\n" );
document.write( "10x+20 =240<BR>\n" );
document.write( "10x=220<BR>\n" );
document.write( "x=22\r<BR>\n" );
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document.write( "Rate of fast cyclist:26 km/h<BR>\n" );
document.write( "Rate of slow cyclist:22 km/h </SPAN>\n" );
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