document.write( "Question 1111965: Two pipes can empty pool in 3 hours. If the smaller pipe can empty it in 10 hours alone, how long can a larger pipe empty the pool alone?
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Algebra.Com's Answer #726971 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+t+\"$ = time in hrs for the larger pipe
\n" ); document.write( "to empty the pool
\n" ); document.write( "Rate of emptying for smaller pipe:
\n" ); document.write( "[ 1 pool emptied ] / [ 10 hrs ]
\n" ); document.write( "Rate of emptying for smaller pipe:
\n" ); document.write( "[ 1 pool emptied ] / [ t hrs ]
\n" ); document.write( "Add the rates of emptying to get the rate
\n" ); document.write( "with both pipes together
\n" ); document.write( "-------------------------------------------
\n" ); document.write( " $\"+1%2F10+%2B+1%2Ft+=+1%2F3+\"$
\n" ); document.write( " $\"+1%2Ft+=+10%2F30+-+3%2F30+\"$
\n" ); document.write( " $\"+1%2Ft+=+7%2F30+\"$
\n" ); document.write( "Multiply both sides by $\"+30t+\"$
\n" ); document.write( " $\"+30+=+7t+\"$
\n" ); document.write( " $\"+t+=+4.2857+\"$ hrs
\n" ); document.write( "The larger pipe alone takes 4.2857 hrs
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\n" ); document.write( "check:
\n" ); document.write( " $\"+1%2F10+%2B+1%2F4.2857+=+1%2F3+\"$
\n" ); document.write( " $\"+.1+%2B+.2333+=+.333+\"$
\n" ); document.write( " $\"+.333+=+.333+\"$
\n" ); document.write( "OK
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