document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111915>Question 1111915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars race on a 4 mile oval track. The sum of their rates is 200 miles per hour. Find the rate of each if the faster car gains one lap in 40 minutes. \r<BR>\n" );
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document.write( "My work:<BR>\n" );
document.write( "I know the rate of the slower car is 200-x and the rate of the other car is x. Then I know the time of slower car is 4/(200-x) and the time of the other car is 4/x. The distance for both is 4 miles. I'm not sure what to do with the \"faster car gains one lap in 40 minutes\". Thank you for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726968 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Two cars race on a 4 mile oval track.<BR>\n" );
document.write( " The sum of their rates is 200 miles per hour.<BR>\n" );
document.write( " Find the rate of each if the faster car gains one lap in 40 minutes.<BR>\n" );
document.write( "Let a = the faster car rate<BR>\n" );
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document.write( "In 40 min car a is 4 mi ahead of slower car<BR>\n" );
document.write( "therefore, in one hr it will be 6 mi ahead.<BR>\n" );
document.write( "Car a is 6 mph faster than the slower car<BR>\n" );
document.write( "a + (a-6) = 200<BR>\n" );
document.write( "2a = 206<BR>\n" );
document.write( "a = 103 mph, slower car = 97 mph   </SPAN>\n" );
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