document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111892>Question 1111892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The frustum has regular hexagon bases. The upper base measures 16 ft. on a side and the lower base measures 29 ft. on a side. The altitude of the frustum is 16 ft.  Find the mass of the frustum, if its density is 99 lbs. per cu. ft.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726941 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The frustum has regular hexagon bases. The upper base measures 16 ft. on a side and the lower base measures 29 ft. on a side. The altitude of the frustum is 16 ft.  Find the mass of the frustum, if its density is 99 lbs. per cu. ft.<BR>\n" );
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document.write( "Find the volume.<BR>\n" );
document.write( "The side length of the hexagon between the bases (8 ft from either) is (29+15)/2 = 22.5 ft<BR>\n" );
document.write( "The area is ns^2*cot(180/n)/4 where n = # of sides & s = side length<BR>\n" );
document.write( "Area = 6*22.5^2*sqrt(3)/4 = 759.375*sqrt(3) sq ft<BR>\n" );
document.write( "Vol = Area*16 = 12150*sqrt(3) cubic ft<BR>\n" );
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document.write( "Mass = Vol*density<BR>\n" );
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