document.write( "Question 1111903: if the simple interest on $1800 exceeds the interest on $1650 in 3 years by $45, find the rate of interest. \n" ); document.write( "

Algebra.Com's Answer #726938 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "I = Prt

\n" ); document.write( "The interest on $1800 for 3 years is $45 more than the interest on $1650 for 3 years:

\n" ); document.write( " $\"1800%28r%29%283%29+=+1650%28r%29%283%29%2B45\"$
\n" ); document.write( " $\"150%28r%29%283%29+=+45\"$
\n" ); document.write( " $\"450r+=+45\"$
\n" ); document.write( " $\"r+=+.10\"$

\n" ); document.write( "The interest rate is .10, or 10%.

\n" ); document.write( "Note that the second line of the calculations shown says that the interest for 3 years on the additional $150 is $45. It would be possible, with a bit of logical reasoning, to use that equation as your starting point for solving the problem. \n" ); document.write( "

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