document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111901>Question 1111901</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a garden store sells bermuda grass seed for $3.65 per pound and argentine bahia grass seed for $6.30 per pound. how many pounds of bermuda grass seed should be mixed with 20 pounds of bahia grass seed to obtain a low maintenance and drought resistance blend that will sell for $4.90? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726935 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Same problem, different numbers<BR>\n" );
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document.write( "how many liters of a 30% salt solution should be mixed with a 80% salt solution to obtain 120 liters of a 60% salt solution?<BR>\n" );
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document.write( "t = amount of 30%<BR>\n" );
document.write( "e = amount of 80%  --- good luck finding 80% salt<BR>\n" );
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document.write( "t + e = 120 (total solution)<BR>\n" );
document.write( "30t + 80e = 120*60 ( total salt)<BR>\n" );
document.write( "etc<BR>\n" );
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