document.write( "Question 1111870: If \"1%2Fx+%2B1%2Fy+=10\" and \"x%2By=2\", what is the value of xy? \n" ); document.write( "
Algebra.Com's Answer #726902 by ikleyn(52847)\"\" \"About 
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document.write( "If  \"1%2Fx+%2B1%2Fy+=10\",  then   \"%28x%2By%29%2Fxy\" = 10.\r\n" );
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document.write( "Replace here (x+y) by 2, since it is given.\r\n" );
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document.write( "You will have  \"2%2F%28xy%29\" = 10,   which implies   xy = \"2%2F10\" = 0.2.\r\n" );
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\n" ); document.write( "\n" ); document.write( "In this case, please refer to the problem ID number 1111870.
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