document.write( "Question 1111845: Two trains leave towns 586 km apart at the same time and travel toward each other. One train travels 13 km/h slower than the other. If they meet in 2 hours, what is the rate of each train?\r
\n" ); document.write( "\n" ); document.write( "slower train:
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Algebra.Com's Answer #726882 by mananth(16946)\"\" \"About 
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Two trains leave towns 586 km apart at the same time and travel toward each other. One train travels 13 km/h slower than the other. If they meet in 2 hours, what is the rate of each train?\r
\n" ); document.write( "\n" ); document.write( "Distance apart 586 km\r
\n" ); document.write( "\n" ); document.write( "First train speed x
\n" ); document.write( "other train speed (x-13)\r
\n" ); document.write( "\n" ); document.write( "time = 2 hours\r
\n" ); document.write( "\n" ); document.write( "The trains are moving towards each other
\n" ); document.write( "add up the speeds\r
\n" ); document.write( "\n" ); document.write( "2x-13\r
\n" ); document.write( "\n" ); document.write( "t=d/s\r
\n" ); document.write( "\n" ); document.write( "2=860/(2x-13)\r
\n" ); document.write( "\n" ); document.write( "4x-26 =860\r
\n" ); document.write( "\n" ); document.write( "4x = 886
\n" ); document.write( "x= 886/4\r
\n" ); document.write( "\n" ); document.write( "x= 221.5 km/h One train
\n" ); document.write( "Other train 221.5-13= 208.5 km/h\r
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