document.write( "Question 1074549: One solution contains 20% alcohol and another solution contains 60% alcohol. Some of each of the two solutions is mixed to produce 10 liters of a 50% solution. How many liters of the 60% solution should be used? \n" ); document.write( "
Algebra.Com's Answer #726852 by amalm06(224)\"\" \"About 
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Use the method of alligation.\r
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\n" ); document.write( "\n" ); document.write( "Denote the 20% alcohol with x and the 60% alcohol with y.\r
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\n" ); document.write( "\n" ); document.write( "Then 50-20=30 and 60-50=10\r
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\n" ); document.write( "\n" ); document.write( "y/x=3/1\r
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\n" ); document.write( "\n" ); document.write( "y=(3/4)(10)=7.5 L (Answer)
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