document.write( "Question 1074549: One solution contains 20% alcohol and another solution contains 60% alcohol. Some of each of the two solutions is mixed to produce 10 liters of a 50% solution. How many liters of the 60% solution should be used? \n" ); document.write( "
Algebra.Com's Answer #726852 by amalm06(224)![]() ![]() You can put this solution on YOUR website! Use the method of alligation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Denote the 20% alcohol with x and the 60% alcohol with y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then 50-20=30 and 60-50=10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y/x=3/1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=(3/4)(10)=7.5 L (Answer) \n" ); document.write( " |