document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111650>Question 1111650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have one type of candy that sells for $4.30/lb and another type of candy that sells for $9.10/lb. You would like to have 43.2 lbs of a candy mixture that sells for $8.10/lb. How much of each candy will you need to obtain the desired mixture </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726850 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem can be solved quickly using the method of alligation.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Represent the $4.30 candy as x and the $9.10 candy as y.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Then 8.10-4.30=3.80 and 9.10-8.10=1. So that x/y=1/3.80\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "To find the quantity of x relative to the mixture:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(1/4.80)(43.2)=9 lb (Answer)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y= 43.2-9=34.2 lb (Answer) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );