document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14584>Question 14584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times the first of two numbers decreased by the second number equals 9. Twice the first number increased by the second number equals 11. Find the two numbers. I need a system of equations to solve the problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7268 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the first number and y = the second number.  You can write:\r<BR>\n" );
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document.write( "3x - y = 9  Three times the 1st number (3x) decreased by the 2nd number (-y) = 9<BR>\n" );
document.write( "2x + y = 11 Two times the 1st number (2x) increased by the 2nd number (+y) = 11\r<BR>\n" );
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document.write( "There are the two equations you need.  Can you take it from here? </SPAN>\n" );
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