document.write( "Question 1111745: Find the perpendicular distance between the line y=(5/13)x + 5 and the origin. \n" ); document.write( "
Algebra.Com's Answer #726758 by KMST(5328)\"\" \"About 
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Distance from a point to a line is always measured along a perpendicular, of course.
\n" ); document.write( "If you were at point P in the sketch below,along what path would you measure your distance to the pool?
\n" ); document.write( " along what path would you measure your distance to the pool, d, e, or f?
\n" ); document.write( "
\n" ); document.write( "MY GUESS AS TO THE EXPECTED SOLUTION:
\n" ); document.write( "Your teacher (or textbook) has probably given you the formula
\n" ); document.write( "to calculate the distance between a point \"P%28x%5BP%5D%2Cy%5BP%5D%29\"
\n" ); document.write( "and a line with equation \"ax%2Bby%2Bc=0\" as
\n" ); document.write( "\"distance\"\"%22=%22\"\"abs%28ax%5BP%5D%2Bby%5BP%5D%2Bc%29%2Fsqrt%28a%5E2%2Bb%5E2%29\" .
\n" ); document.write( "
\n" ); document.write( "In this case, your point is the origin \"O%280%2C0%29\" ,
\n" ); document.write( "so \"x%5BP%5D=y%5BP%5D=0\" , and
\n" ); document.write( "\"y=%285%2F13%29x+%2B+5\" can be transformed,
\n" ); document.write( "by rearranging and multiplying both sides of the equal sign time \"13\" ,
\n" ); document.write( "to get the equivalent equation
\n" ); document.write( "\"5x-13y%2B65=0\" , with \"a=5\", \"b=-13\" , \"c=65\" .
\n" ); document.write( "
\n" ); document.write( "So, in this case,
\n" ); document.write( "\"distance\"\"%22=%22\"\"65%2Fsqrt%285%5E2%2B%28-13%29%5E2%29\"}\"%22=%22\"\"65%2Fsqrt%2825%2B169%29\"}\"%22=%22\"\"65%2Fsqrt%28194%29\" .
\n" ); document.write( "The elegant way to express the exact value is
\n" ); document.write( "\"distance=65sqrt%28194%29%2F194\"
\n" ); document.write( "The approximate value for that irrational number
\n" ); document.write( "is the never ending, non-repeating, decima \"%22l4.666728....%22\" .
\n" ); document.write( "
\n" ); document.write( "ANOTHER APPROACH:
\n" ); document.write( "It is easy to see that the x- and y-intercepts are the points
\n" ); document.write( "\"A%28-13%2C0%29\" and \"B%280%2C5%29\" .
\n" ); document.write( "If you look at the line, the axes,
\n" ); document.write( "and the path along which you would measure the distance to the origin,
\n" ); document.write( "you see right triangles:
\n" ); document.write( "
\n" ); document.write( "When people see right triangles they think about
\n" ); document.write( "trigonometric ratios,
\n" ); document.write( "or the Pythagorean theorem,
\n" ); document.write( "or similar triangles.
\n" ); document.write( "Each of those ideas can also lead to a solution,
\n" ); document.write( "as another tutor showed you for trigonometric ratios.
\n" ); document.write( "
\n" ); document.write( "USING THE PYTHAGOREAN THEOREM:
\n" ); document.write( "The most obvious right triangle in the sketch above is big triangle ABO ,
\n" ); document.write( "with hypotenuse \"AB=sqrt%2813%5E2%2B5%5E2%29=sqrt%28169%2B25%29=sqrt%28194%29\" ,
\n" ); document.write( "calculated using the Pythagorean theorem.
\n" ); document.write( "The area of ABO is \"area=5%2A13%2F2\" ,
\n" ); document.write( "calculated as \"area=base%2Aheight%2F2\" ,
\n" ); document.write( "using AO as the base and OB as the height.
\n" ); document.write( "As we know that the distance \"green%28d%29\"
\n" ); document.write( "is measured along line OC, perpendicular to AB,
\n" ); document.write( "we could also calculate the area as \"area=AB%2Ad%2F2\" ,
\n" ); document.write( "using \"AB\" as the base and \"green%28d%29=OC\" as the height.
\n" ); document.write( "Substituting, and combining both ways of calculating area
\n" ); document.write( "\"sqrt%28194%29d%2F2=5%2A13%2F2\"
\n" ); document.write( "\"sqrt%28194%29d=5%2A13\"
\n" ); document.write( "\"d=5%2A13%2Fsqrt%28194%29=65%2Fsqrt%28194%29=65sqrt%28194%29%2F194=aproximately14.67\"
\n" ); document.write( "
\n" ); document.write( "USING SIMILAR TRIANGLES:
\n" ); document.write( "Triangles ABO and BCO are both right triangles,
\n" ); document.write( "and they both have the same angle at B,
\n" ); document.write( "so they are similar triangles,
\n" ); document.write( "with BCO being a scaled-down version of ABO.
\n" ); document.write( "The ratio of corresponding sides is the scale factor,
\n" ); document.write( "the same for the long leg as for the hypotenuse
\n" ); document.write( "\"d%2F13=5%2Fsqrt%28194%29\" , so
\n" ); document.write( "\"d=5%2A13%2Fsqrt%28194%29=65%2Fsqrt%28194%29=65sqrt%28194%29%2F194=aproximately14.67\" .
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