document.write( "Question 1111745: Find the perpendicular distance between the line y=(5/13)x + 5 and the origin. \n" ); document.write( "
Algebra.Com's Answer #726758 by KMST(5328)![]() ![]() You can put this solution on YOUR website! Distance from a point to a line is always measured along a perpendicular, of course. \n" ); document.write( "If you were at point P in the sketch below,along what path would you measure your distance to the pool? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "MY GUESS AS TO THE EXPECTED SOLUTION: \n" ); document.write( "Your teacher (or textbook) has probably given you the formula \n" ); document.write( "to calculate the distance between a point \n" ); document.write( "and a line with equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In this case, your point is the origin \n" ); document.write( "so \n" ); document.write( " \n" ); document.write( "by rearranging and multiplying both sides of the equal sign time \n" ); document.write( "to get the equivalent equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, in this case, \n" ); document.write( " \n" ); document.write( "The elegant way to express the exact value is \n" ); document.write( " \n" ); document.write( "The approximate value for that irrational number \n" ); document.write( "is the never ending, non-repeating, decima \n" ); document.write( " \n" ); document.write( "ANOTHER APPROACH: \n" ); document.write( "It is easy to see that the x- and y-intercepts are the points \n" ); document.write( " \n" ); document.write( "If you look at the line, the axes, \n" ); document.write( "and the path along which you would measure the distance to the origin, \n" ); document.write( "you see right triangles: \n" ); document.write( " \n" ); document.write( "When people see right triangles they think about \n" ); document.write( "trigonometric ratios, \n" ); document.write( "or the Pythagorean theorem, \n" ); document.write( "or similar triangles. \n" ); document.write( "Each of those ideas can also lead to a solution, \n" ); document.write( "as another tutor showed you for trigonometric ratios. \n" ); document.write( " \n" ); document.write( "USING THE PYTHAGOREAN THEOREM: \n" ); document.write( "The most obvious right triangle in the sketch above is big triangle ABO , \n" ); document.write( "with hypotenuse \n" ); document.write( "calculated using the Pythagorean theorem. \n" ); document.write( "The area of ABO is \n" ); document.write( "calculated as \n" ); document.write( "using AO as the base and OB as the height. \n" ); document.write( "As we know that the distance \n" ); document.write( "is measured along line OC, perpendicular to AB, \n" ); document.write( "we could also calculate the area as \n" ); document.write( "using \n" ); document.write( "Substituting, and combining both ways of calculating area \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "USING SIMILAR TRIANGLES: \n" ); document.write( "Triangles ABO and BCO are both right triangles, \n" ); document.write( "and they both have the same angle at B, \n" ); document.write( "so they are similar triangles, \n" ); document.write( "with BCO being a scaled-down version of ABO. \n" ); document.write( "The ratio of corresponding sides is the scale factor, \n" ); document.write( "the same for the long leg as for the hypotenuse \n" ); document.write( " \n" ); document.write( " |