document.write( "Question 1111708: A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of 35 miles per gallon of gas. During one particular week, the two cars went a combined total of 825 miles, for a total gas consumption of 35 gallons. How many gallons were consumed by each of the two cars that week? \r
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document.write( "First car: ______ gallons
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document.write( "Second car: ______ gallons \n" );
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Algebra.Com's Answer #726712 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Car I x gallons for the for the week \n" ); document.write( "Car II y gallons for the for the week \n" ); document.write( "Equation for tickets total distance \n" ); document.write( " \n" ); document.write( "1 x + 1 y = 35 .............1 \n" ); document.write( " \n" ); document.write( "Equation for amount spent \n" ); document.write( "15 x + 35 y = 825 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -35.00 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-35.00 x -35.00 y = -1225.00 \n" ); document.write( "15.00 35.00 y = 825.00 \n" ); document.write( "Add the two equations \n" ); document.write( "-20.00 x = -400.00 \n" ); document.write( "/ -20.00 \n" ); document.write( "x = 20.00 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1.00 x + 1.00 y = 35.00 \n" ); document.write( "20.00 + 1.00 y = 35.00 \n" ); document.write( " 1.00 y = 15.00 \n" ); document.write( " y= 15.00 \n" ); document.write( " \n" ); document.write( "Car I 20.00 gallons for the for the week \n" ); document.write( "Car II 15.00 gallons for the for the week \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |