document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111669>Question 1111669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> writen in logarithm form. <BR>\n" );
document.write( "1/81=3^-4\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726653 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> basic definition of logs says:\r<BR>\n" );
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document.write( "y = b^x if and only if logb(y) = x\r<BR>\n" );
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document.write( "your equation says 1/81 = 3^-4\r<BR>\n" );
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document.write( "replace y with 1/81 and b with 3 and x with -4 and the basic definition of logs equation becomes:\r<BR>\n" );
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document.write( "1/81 = 3^-4 if and only if log3(1/81) = -4\r<BR>\n" );
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document.write( "you can use your calculator to find the value of log3(1/81).\r<BR>\n" );
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document.write( "you use the log base conversion formula of log3(1/81) = log(1/81)/log(3).\r<BR>\n" );
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document.write( "use the calculator to find that log(1/81)/log(3) = -4.\r<BR>\n" );
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document.write( "your solution is:\r<BR>\n" );
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document.write( "1/81 = 3^-4 if and only if log3(1/81) = -4\r<BR>\n" );
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