document.write( "Question 1111654: Log10(xsquaare-4x+7)=2 \n" ); document.write( "
Algebra.Com's Answer #726648 by rothauserc(4718) You can put this solution on YOUR website! log(base 10) (x^2 -4x +7) = 2 \n" ); document.write( ": \n" ); document.write( "use definition of logarithms \n" ); document.write( ": \n" ); document.write( "x^2 -4x +7 = 10^2 = 100 \n" ); document.write( ": \n" ); document.write( "x^2 -4x -93 = 0 \n" ); document.write( ": \n" ); document.write( "x^2 -4x = 93 \n" ); document.write( ": \n" ); document.write( "x^2 -4x +4 = 93 +4 = 97 \n" ); document.write( ": \n" ); document.write( "(x-2)^2 = 97 \n" ); document.write( ": \n" ); document.write( "x-2 = square root(97) \n" ); document.write( ": \n" ); document.write( "***************************** \n" ); document.write( "x = 2 + square root(97) \n" ); document.write( "x = 2 - square root(97) \n" ); document.write( "***************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |