document.write( "Question 1111654: Log10(xsquaare-4x+7)=2 \n" ); document.write( "
Algebra.Com's Answer #726648 by rothauserc(4718)\"\" \"About 
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log(base 10) (x^2 -4x +7) = 2
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\n" ); document.write( "use definition of logarithms
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\n" ); document.write( "x^2 -4x +7 = 10^2 = 100
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\n" ); document.write( "x^2 -4x -93 = 0
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\n" ); document.write( "x^2 -4x = 93
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\n" ); document.write( "x^2 -4x +4 = 93 +4 = 97
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\n" ); document.write( "(x-2)^2 = 97
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\n" ); document.write( "x-2 = square root(97)
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\n" ); document.write( "x = 2 + square root(97)
\n" ); document.write( "x = 2 - square root(97)
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