document.write( "Question 1111570: Problem Page Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $25 and same-day tickets cost $20 . For one performance, there were 35 tickets sold in all, and the total amount paid for them was $800 . How many tickets of each type were sold? \n" ); document.write( "
Algebra.Com's Answer #726627 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Here is a quick path to the solution using mental arithmetic and some logical reasoning.

\n" ); document.write( "(1) If all 35 tickets had been same day tickets, the total amount paid would have been $700, which is $100 less than the actual total.
\n" ); document.write( "(2) Each advance ticket costs $5 more than each same day ticket.
\n" ); document.write( "(3) To make the other $100 of the actual total, the number of advance tickets has to be 100/5 = 20.

\n" ); document.write( "So there were 20 advance tickets, which means there were 35-20=15 same day tickets.
\n" ); document.write( "
\n" );