document.write( "Question 1111551: The base of an isosceles trapezoid measure 32cm and 20cm. find the area if the non-parallel sides measure 16cm each. \n" ); document.write( "
Algebra.Com's Answer #726619 by ikleyn(52790)\"\" \"About 
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document.write( "Draw the altitude to the base from the vertex.\r\n" );
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document.write( "Then you will get a right angled triangle with the hypotenuse of 16 cm long.\r\n" );
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document.write( "The length of one leg is  \"%2832-20%29%2F2\" = 6 cm.\r\n" );
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document.write( "Then the altitude is \"sqrt%2816%5E2+-+6%5E2%29\" = \"sqrt%28256-36%29\" = \"sqrt%28220%29\" = \"2%2Asqrt%2855%29\".\r\n" );
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document.write( "The area of the trapezoid is  \"2%2Asqrt%2855%29%2A%28%2832%2B20%29%2F2%29\" = \"52%2Asqrt%2855%29\" cm^2.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Be aware:  The solution and the answer by the @josgarithmetic are   W R O N G.\r
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