document.write( "Question 1111518: $12,305 is invested, part at 10% and the rest at 8%. If the interest earned from the amount invested at 10% exceeds the interest earned from the amount invested at 8% by 1025.30, how much is invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #726599 by mananth(16946) $\"\"$ $\"About$

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Part I 10.00% per annum ------------- x
\n" ); document.write( "Part II 8.00% per annum ------------ y
\n" ); document.write( " total investment 12305
\n" ); document.write( " Interest----- from greater part = 10.00% x
\n" ); document.write( " Interest from smaller part= 8.00% y
\n" ); document.write( " greater by 1025.3
\n" ); document.write( " 10.00% x = 8.00% y + 1025.3
\n" ); document.write( " multiply by 100
\n" ); document.write( " 10 x - -8 y = 102530 --------1
\n" ); document.write( "x+ 1 y = 12305 -------- 2
\n" ); document.write( "eliminate y
\n" ); document.write( "Multiply 1 by 1
\n" ); document.write( "Multiply 2 by 8
\n" ); document.write( "we get
\n" ); document.write( "10 x - -8 y = 102530
\n" ); document.write( "8 x - 8 y = 98440
\n" ); document.write( "18 x = 200970
\n" ); document.write( "/ 18
\n" ); document.write( " x= 11165
\n" ); document.write( "Plug the value of x in in 1
\n" ); document.write( "111650 -8 y = 102530
\n" ); document.write( " -8 y = 102530 -111650
\n" ); document.write( " -8 y = -9120
\n" ); document.write( " / -8
\n" ); document.write( " y= 1140.00
\n" ); document.write( "$ 11165 at 10.00%
\n" ); document.write( "$ 1140.00 at 8.00%
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "1116.5 = 91.20 + 1025.3
\n" ); document.write( " 1116.50
\n" ); document.write( " \n" ); document.write( "

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