document.write( "Question 1111571: Two friends have built a lemonade stand, and they plan to start out by selling 20 liters of lemonade containing 23% lemon juice. To make this, they will mix some homemade lemonade containing 27% lemon juice with some store-bought lemonade that contains 22% lemon juice. How much of each type should the friends use? \n" ); document.write( "
Algebra.Com's Answer #726574 by amalm06(224)\"\" \"About 
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The problem can be solved in two different ways. Consider first the following system of equations:\r
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\n" ); document.write( "\n" ); document.write( "x+y=20\r
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\n" ); document.write( "\n" ); document.write( "0.27x+0.22y=(0.23)(20)\r
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\n" ); document.write( "\n" ); document.write( "Solving the above equations for x and y will give you the relevant quantities.\r
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\n" ); document.write( "\n" ); document.write( "The other method is that of alligation. \r
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\n" ); document.write( "\n" ); document.write( "Let S1 denote the 22% solution and S2 denote the 27% solution. \r
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\n" ); document.write( "\n" ); document.write( "Then 23-22=1 and 27-23=4. So that S1:S2=4/1. This mean means that we have 4 parts of S1 for every 5 parts of mixture. We can find S1 and S2 as follows:\r
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\n" ); document.write( "\n" ); document.write( "S1=(4/5)(20) = 16 L (Answer)\r
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\n" ); document.write( "\n" ); document.write( "S2=20-16=4 L (Answer) \n" ); document.write( "
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