document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=433829>Question 433829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much clay do you need to add to 6 ft^3 of soil with 30% clay in order to make a soil with 72% clay?\r<BR>\n" );
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document.write( "I suck at setting problems up, but can solve them fine. Having troubles with this one.\r<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "Tyler </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726538 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the method of alligation.\r<BR>\n" );
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document.write( "Let S denote the soil and C denote the clay.\r<BR>\n" );
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document.write( "Then 100-72=28 and 72-30=42\r<BR>\n" );
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document.write( "Therefore, the ratio of soil to clay is 28/42\r<BR>\n" );
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document.write( "Since there are 6 ft^3 of soil, (42/28)(6 ft^3) = 9 ft^3 (Answer)  </SPAN>\n" );
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