document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=746137>Question 746137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters each of a 15% acid solution and a 25% acid solution must be used to produce 80 liters of a 20% acid solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726537 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem can be solved using the method of alligation.\r<BR>\n" );
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document.write( "Let S1 denote the 15% acid solution.\r<BR>\n" );
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document.write( "Let S2 denote the 25% acid solution.\r<BR>\n" );
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document.write( "Then 25-20=5 and 20-15=5\r<BR>\n" );
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document.write( "Therefore, the ratio of S1/S2=1/1\r<BR>\n" );
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document.write( "Since there are 2 parts of mixture for every 1 part of S1 (WLOG), we have the following relation:\r<BR>\n" );
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document.write( "S1=(1/2)(80)= 40 L (Answer)\r<BR>\n" );
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document.write( "S2=80-40= 40 L (Answer)  </SPAN>\n" );
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