document.write( "Question 1111503: How long will it take an investment of $2000 to double if the investment earns interest at the rate of 5%/year compounded monthly? \n" ); document.write( "
Algebra.Com's Answer #726518 by mananth(16946)\"\" \"About 
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Find number of years
\n" ); document.write( "Principal P = 2000
\n" ); document.write( "Amount= 4000
\n" ); document.write( "years=n
\n" ); document.write( "compounded (t) 12 (monthly)
\n" ); document.write( "Rate = 5 (5%/12) -> 0.004166667
\n" ); document.write( "Amount = P*((n+r)/n)^n*t
\n" ); document.write( "
\n" ); document.write( "4000 = 2000 *( 1 + 0.004166667 )^ n*t
\n" ); document.write( "2 = *( 1 + 0.004166667 )^ n* 12
\n" ); document.write( "ln 2 = 12 n *ln 1.004166667
\n" ); document.write( " 0.693147181 = 12 0.00415801 *n
\n" ); document.write( " 13.89180473 = n\r
\n" ); document.write( "\n" ); document.write( "Number of years = 13.89
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