document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111462>Question 1111462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A gardener needs to cultivate a triangular plot of land. One angle of the garden is 47,and two sides adjacent to the angle are 77 feet and 76 feet. What is the area of the plot of land. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726464 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726464\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find third side by using Law of Cosines<BR>\n" );
document.write( "c^2=a^2+b^2-2abcos C=77^2+76^2-2(76)(77)cos 47<BR>\n" );
document.write( "=11705-11704 * 0.682<BR>\n" );
document.write( "=11705-7982.13<BR>\n" );
document.write( "=3722.87<BR>\n" );
document.write( "c=61.01, use 61<BR>\n" );
document.write( "Heron's formula<BR>\n" );
document.write( "A= sqrt (s*(s-a)(s-b)(s-c)), s= (1/2)(a+b+c)=107<BR>\n" );
document.write( "A=sqrt (107*40*41*46)=2841 ft^2                                                                                                                                                                                                            <BR>\n" );
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