document.write( "Question 1111329: Lenlen is 2years younger than her brother.three times lenlen's age is less than four times her brothers age diminished by tweleve.find the least possible age of lenlen
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #726381 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Lenlen is 2years younger than her brother. \n" ); document.write( "L = b - 2\r \n" ); document.write( "\n" ); document.write( "three times lenlen's age is less than four times her brothers age diminished by twelve. \n" ); document.write( "3L < 4b - 12 \n" ); document.write( "Replace L with (b-2) \n" ); document.write( "3(b-2) < 4b - 12 \n" ); document.write( "3b - 6 < 4b - 12 \n" ); document.write( "3b - 4b < -12 + 6 \n" ); document.write( "-b < -6 \n" ); document.write( "multiply by -1, this reverses the inequality sign \n" ); document.write( "b > 6 \n" ); document.write( ": \n" ); document.write( "L = b - 2 \n" ); document.write( "L > 6 - 2 \n" ); document.write( "L > 4 \n" ); document.write( ": \n" ); document.write( "find the least possible age of lenlen: 5 yrs old \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this. b = 7 (two more than L) \n" ); document.write( "\"three times lenlen's age is less than four times her brothers age diminished by twelve\" \n" ); document.write( "3(5) < 4(7) - 12 \n" ); document.write( "15 < 28 - 12 \n" ); document.write( "15 < 16; true! \n" ); document.write( " |