document.write( "Question 1111379: If the police have 8 suspects, how many different ways can they select 5 for a lineup?
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document.write( "The answer that I came up with was 6720 ways. But its wrong. Was i supposed to do this problem as a permutation or a combination? Or neither? \n" );
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Algebra.Com's Answer #726357 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If the police have 8 suspects, how many different ways can they select 5 for a lineup? \n" ); document.write( "The answer that I came up with was 6720 ways. But its wrong. Was i supposed to do this problem as a permutation or a combination? Or neither? \n" ); document.write( "----- \n" ); document.write( "You are selecting groups so use a combination formula. \n" ); document.write( "8C5 = 8C3 = (8*7*6)/(1*2*3) = 8*7 = 56 \n" ); document.write( "--------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------------ \n" ); document.write( " |