document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111362>Question 1111362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question 3 Nicole's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs $5.30 Nicole per pound, and type B coffee costs $4.05 per pound. This month, Nicole made 169 pounds of the blend, for a total cost of $803.20. How many pounds of type A coffee did she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726345 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Type A = 5.30/lb<BR>\n" );
document.write( "Type B = 4.05/lb<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "1st equation<BR>\n" );
document.write( "A + B = 169 lbs, subtract A from both sides:<BR>\n" );
document.write( "B = 169-A<BR>\n" );
document.write( "2nd equation<BR>\n" );
document.write( "5.30A + 4.05B = 803.20<BR>\n" );
document.write( "In this second equation, substitute for B with the result of the 1st equation:<BR>\n" );
document.write( "5.30A + 4.05(169-A) = 803.2<BR>\n" );
document.write( "5.30A + 684.45 - 4.05A = 803.2<BR>\n" );
document.write( "1.25A = 118.75<BR>\n" );
document.write( "A = 95<BR>\n" );
document.write( "so there you have it, you need 95 pounds of coffee A.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );