document.write( "Question 1111345: Find the minimum slope of the line tangent to the curve y = x³-3x²+6x+3.
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Algebra.Com's Answer #726330 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! derivative of x^3-3x^2+6x+3 is 3x^2-6x+6\r \n" ); document.write( "\n" ); document.write( "The derivative is the slope of the line. The minimum value is where x=-b/2a, like any quadratic. \n" ); document.write( "That is x=6/6=1 \n" ); document.write( "The slope is 3-6+6 or 3. The point on the original function is (1, 7)\r \n" ); document.write( "\n" ); document.write( " |