document.write( "Question 1111218: Find b:a, from the equation 12a^2-25ab+7b^2 =0 given that the b/a is a proper fraction? \n" ); document.write( "
Algebra.Com's Answer #726283 by mananth(16946)\"\" \"About 
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\"12a%5E2-25ab%2B7b%5E2+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"12a%5E2+-21ab-4ab%2B7b%5E2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3a%284a-7b%29-b%284a-7b%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%283a-b%29%284a-7b%29+=0\"\r
\n" ); document.write( "\n" ); document.write( "either (3a-b) =0 or (4a-7b)=0
\n" ); document.write( "3a-b=0
\n" ); document.write( "3a=b
\n" ); document.write( "a/b =1/2\r
\n" ); document.write( "\n" ); document.write( "Or
\n" ); document.write( "4a-7b=0
\n" ); document.write( "4a=7b
\n" ); document.write( "a/b = 7/4\r
\n" ); document.write( "\n" ); document.write( "choose one which is a proper fraction
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