document.write( "Question 1111206: solve by using elimination method
\n" ); document.write( "x+y=2
\n" ); document.write( "y+z=4
\n" ); document.write( "z+x=9
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Algebra.Com's Answer #726210 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "x+y=2
\n" ); document.write( "y+z=4
\n" ); document.write( "z+x=9
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document.write( "For this system\r\n" );
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document.write( "x + y = 2    (1)\r\n" );
document.write( "y + z = 4    (2)\r\n" );
document.write( "z + x = 9    (3)\r\n" );
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document.write( "there is SPECIAL method of solution.\r\n" );
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document.write( "First, add all three equations (1), (2) and (3).  You will get\r\n" );
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document.write( "2x + 2y + 2z = 15,     or, equivalently,\r\n" );
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document.write( "x + y + z = 7.5.    (4)\r\n" );
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document.write( "Now subtract eq(1) from eq(4). You will get\r\n" );
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document.write( "z = 7.5 - 2 = 5.5.    The unknown \"z\" is just found.\r\n" );
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document.write( "Next subtract eq(2) from eq(4). You will get\r\n" );
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document.write( "x = 7.5 - 4 = 3.5.    The unknown \"x\" is just found.\r\n" );
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document.write( "Finally, subtract eq(3) from eq(4). You will get\r\n" );
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document.write( "y = 7.5 - 9 = -1.5.    The unknown \"y\" is just found.\r\n" );
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document.write( "Answer.  x= 3.5;  y= -1.5;  z= 3.5.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.   //   It is one of the versions of the  Elimination method.\r
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