document.write( "Question 1111103: Stephen has a bowl of M&Ms, which he is eating at a constant speed. He began with 28 pounds. It will take him 7 hours to finish the bowl. When considering the length of time he has been eating and the pounds of M&Ms LEFT, write an equation. Also, find the x and y intercept. \n" ); document.write( "
Algebra.Com's Answer #726112 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+y+\" = pounds of M&Ms left in bowl
\n" ); document.write( "Let \"+x+\" = length of time in hrs he has been eating
\n" ); document.write( "--------------------------------------------
\n" ); document.write( "His rate of eating is \"+28%2F7+=+4+\" pounds/hr
\n" ); document.write( "[ pounds of M&Ms in bowl ] / [ rate of eating them ] = [ time to eat them ]
\n" ); document.write( "\"+28%2F4+=+7+\" hrs
\n" ); document.write( "----------------------
\n" ); document.write( "I have given myself the point ( 7, 0 ) on the line
\n" ); document.write( "( there is zero M&Ms left in bowl after \"+7+\" hrs )
\n" ); document.write( "and for slope, \"+m+=+-4+\"
\n" ); document.write( "( after each hr, there is less in the bowl )
\n" ); document.write( "\"+y+=+m%2Ax+%2B+b+\"
\n" ); document.write( "\"+y+=+-4%2Ax+%2B+b+\"
\n" ); document.write( "\"+0+=+-4%2A7+%2B+b+\"
\n" ); document.write( "\"+b+=+28+\"
\n" ); document.write( "\"+y+=+-4x+%2B+28+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "x-intercept:
\n" ); document.write( "( x, 0 )
\n" ); document.write( "\"+0+=+-4x+%2B+28+\"
\n" ); document.write( "\"+4x+=+28+\"
\n" ); document.write( "\"+x+=+7+\"
\n" ); document.write( "( 7, 0 )
\n" ); document.write( "-------------------
\n" ); document.write( "y-intercept:
\n" ); document.write( "( 0, y )
\n" ); document.write( "\"+y+=+-4%2A0+%2B+28+\"
\n" ); document.write( "\"+y+=+28+\"
\n" ); document.write( "( 0, 28 )\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );