document.write( "Question 1111090: Katy invests a total of $24,000 in two accounts paying 7% and 13% simple interest, respectively. How much was invested in each account if, after one year, the total interest was $2,790.00.\r
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document.write( "A) Enter an equation that uses the information as it is given that can be used to solve this problem. Use
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document.write( "x
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document.write( " as your variable to represent the amount of money invested in the account paying 7% simple interest.
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document.write( "Equation:
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document.write( "B) The answers are:
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document.write( "$
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document.write( " was invested at 7% and
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document.write( " was invested at 13%. \n" );
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Algebra.Com's Answer #726097 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Katy invests a total of $24,000 \r \n" ); document.write( "\n" ); document.write( " account paying 7% ....x\r \n" ); document.write( "\n" ); document.write( "amount paying 13% ,....24000-x\r \n" ); document.write( "\n" ); document.write( "7%x+13%(24000-x) = 2790\r \n" ); document.write( "\n" ); document.write( "multiply equation by 100 \n" ); document.write( "7x+13(24000-x) = 279000\r \n" ); document.write( "\n" ); document.write( "7x+312000-13x=279000 \n" ); document.write( "simplify \n" ); document.write( "6x= 33000 \n" ); document.write( "x=5500 ... at 7%\r \n" ); document.write( "\n" ); document.write( "24000-5500= 18500 at 13%\r \n" ); document.write( "\n" ); document.write( "CHECK\r \n" ); document.write( "\n" ); document.write( "18500*13% +5500*7% =2790\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |