document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111048>Question 1111048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs to strengthen a 15% alcoholic solution to one of 32% alcohol .how much pure alcohl should be added to 800 ml of 15% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726055 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the standard algebraic solution method that requires only a few simple calculations.<br><BR>\n" );
document.write( "(1) Find how far the desired 32% is from the 15% of the original solution and from the 100% of the pure alcohol.<BR>\n" );
document.write( "100-32 = 68; 32-15 = 17<br><BR>\n" );
document.write( "(2) The ratio of the two numbers from (1) is the ratio in which the two ingredients must be mixed.<BR>\n" );
document.write( "68:17 = 4:1<br><BR>\n" );
document.write( "Since the 32% is closer to 15% than to 100%, you need 4 parts of the original solution to 1 part of the added pure alcohol.  In other words, the amount of pure alcohol to be added should be 1/4 the amount of the original mixture.<BR>\n" );
document.write( "1/4 of 800ml = 200ml<br><BR>\n" );
document.write( "Answer: He needs to add 200ml of pure alcohol. </SPAN>\n" );
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