document.write( "Question 1111039: Kim is 6 years more than twice Timothy's age. 2 years ago, Kim was three times as old as Timothy. How old was Kim 2 years ago? Please write the equation.
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Algebra.Com's Answer #726053 by KMST(5328) $\"\"$ $\"About$

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To make it simpler,
\n" ); document.write( "let's make $\"t\"$ =Timothy's age now.
\n" ); document.write( "As \"Kim is 6 years more than twice Timothy's age\", Kin's age now is
\n" ); document.write( " $\"2t%2B6\"$ .
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\n" ); document.write( "Two years ago,
\n" ); document.write( "Timothy's age was $\"t-2\"$ ,
\n" ); document.write( "and Kim's age as $\"2t%2B6-2=2t%2B4\"$ .
\n" ); document.write( "If at that time, \"Kim was three times as old as Timothy\",
\n" ); document.write( " $\"2t%2B4=3%28t-2%29\"$
\n" ); document.write( "In the equation above, we solve for $\"t\"$ ,
\n" ); document.write( "and then we calculate Kim's age 2 years ago as $\"2t%2B4\"$ .
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\n" ); document.write( "Solving:
\n" ); document.write( " $\"2t%2B4=3%28t-2%29\"$
\n" ); document.write( " $\"2t%2B4=3t-6\"$
\n" ); document.write( " $\"4%2B6=3t-2t\"$
\n" ); document.write( " $\"t=10\"$
\n" ); document.write( " $\"2t%2B4=2%2A10%2B4=20%2B4=highlight%2824%29\"$ .
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\n" ); document.write( "Let's check and see if it makes sense.
\n" ); document.write( " $\"t=10\"$ means Timothy is 10 years old.
\n" ); document.write( "If Kim is 6 years more than twice that, she is $\"2%2A10%2B6=20%2B6=26\"$ .
\n" ); document.write( "Two years ago Timothy must have been $\"10-2=8\"$ ,
\n" ); document.write( "and Kim must have been $\"26-2=24\"$ , which is three times as old as Timothy.
\n" ); document.write( "It checks. All makes sense. \n" ); document.write( "

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