document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111051>Question 1111051</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the radius of the circle :\r<BR>\n" );
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document.write( "a)when theta=90  ,A=20cm^2 ?\r<BR>\n" );
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document.write( "NOTE:A is chord area  ?\r<BR>\n" );
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document.write( "please helpppp ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726045 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726045\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The chord area = (R^2/2) * ( ((theta * pi)/180) - sin theta), where R is the radius<BR>\n" );
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document.write( "Note the above says the chord area = area of circular sector - area of triangular portion<BR>\n" );
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document.write( "we are given the chord area = 20 cm^2 and theta = 90<BR>\n" );
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document.write( "20 = (R^2/2) * ( ((90 * pi)/180) - sin 90)<BR>\n" );
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document.write( "(R^2/2) * ( (pi/2) - 1) = 20<BR>\n" );
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document.write( "(R^2/2) * 0.5708 = 20<BR>\n" );
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document.write( "(R^2/2) = 35.0385<BR>\n" );
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document.write( "R^2 = 70.077<BR>\n" );
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document.write( "Area of circle = pi * R^2 = pi * 70.077 = 220.1534 approximately 220 cm^2<BR>\n" );
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