document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1111036>Question 1111036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a certain number of two digits, the sum of the digits increased by 3, is twice the unit digit. If the number is divided by the sum of the digits, the quotient is 4 and the remainder is 3. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #726035 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=726035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let units digit be x<BR>\n" );
document.write( "and tens digit be y\r<BR>\n" );
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document.write( "x+y+3 = 2x<BR>\n" );
document.write( "x-y=3........(1)\r<BR>\n" );
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document.write( "(10y+x)= (x+y) *4 +3\r<BR>\n" );
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document.write( "subtract the equations\r<BR>\n" );
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document.write( "6y-3x =3<BR>\n" );
document.write( "2y-x=1........(2)\r<BR>\n" );
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document.write( "add 1 & 2<BR>\n" );
document.write( "y=4<BR>\n" );
document.write( "therefore x=7\r<BR>\n" );
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document.write( "Number is 47\r<BR>\n" );
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document.write( " </SPAN>\n" );
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