document.write( "Question 1111031: Wilfred and Wendy have a long distance bike race. Wilfred rides at 20 km/h and has a 2 hour head start. Wendy travels at 28 km/h. How long does it take for Wendy to catch up to Wilfred? Use distance = speed × time.
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Algebra.Com's Answer #726032 by ikleyn(52832) $\"\"$ $\"About$

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document.write( "How long does it take for Wendy to catch up to Wilfred =  =  = 5 hours.\r\n" );
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document.write( "Wilfred is 2*20 = 40 km ahead (head start).   It is the initial distance.  And it is the NUMERATOR of my formula.\r\n" );
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document.write( "Their relative speed is 28-20 = 8 km/h   meaning that the distance between them decreases at the rate of 8 km/h.\r\n" );
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document.write( "                                                                           And it is the DENOMINATOR of my formula.\r\n" );
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document.write( "It gives the time to catch up   = 5 hours.\r\n" );
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\n" ); document.write( "See introductory lessons on Travel and Distance problems\r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in opposite directions \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in the same direction (catching up)\r
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\n" ); document.write( "\n" ); document.write( "They are written specially for you.\r
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\n" ); document.write( "\n" ); document.write( "You will find the solutions of many similar problems there.\r
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\n" ); document.write( "\n" ); document.write( "Read them and learn once for all from these lessons on how to solve simple Travel and Distance problems.\r
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\n" ); document.write( "\n" ); document.write( "Become an expert in this area.\r
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