document.write( "Question 1111013: A rectangle is twice as long as it is wide. If both of its dimensions are increased by 4 m, its area is increased by 88 m^2. Find the dimensions of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #726009 by mananth(16946)\"\" \"About 
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let width be x
\n" ); document.write( "length will be 2 x
\n" ); document.write( "Area of rectangle = 2x^2
\n" ); document.write( "both dimensions are increased by 4
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\n" ); document.write( "width = x + 4
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\n" ); document.write( "length = 2 x + 4
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\n" ); document.write( "As per the condition
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\n" ); document.write( "(x+ 4 )*( 2 x+ 4 )= 2 x^2+ 88 )
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\n" ); document.write( "2 x^2+ 4 x+ 8 x 16 = 2 x^2+ 88
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\n" ); document.write( "Simplify
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\n" ); document.write( "12 x= 72
\n" ); document.write( " x= 6
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\n" ); document.write( "width = 6 m
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\n" ); document.write( "length= 12 m
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