document.write( "Question 1110967: Hi, I am hoping you could solve this equation with a step by step picture on how you got what you did at each step. I have an exam and I am really struggling. Thanks\r
\n" ); document.write( "\n" ); document.write( "Numerator: 3+3^(1/3)
\n" ); document.write( "Denominator: 9^(1/3)\r
\n" ); document.write( "\n" ); document.write( "It is actually the cubed root of 3 and the cubed root of 9, I just didnt know how to type that
\n" ); document.write( "

Algebra.Com's Answer #725977 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
I think this is what you want: (you can use 'show source' to see how to format):
\n" ); document.write( "\"+%283%2B+root%283%2C3%29%29+%2F+%28root%283%2C9%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "This is not an equation, it is an expression. The question must be to rationalize the expression (get rid of as many roots as possible, in particular, from the denominator):
\n" ); document.write( "

\n" ); document.write( "\"++%283%2Broot%283%2C3%29%29+%2F+%28root%283%2C9%29%29++\"\r
\n" ); document.write( "\n" ); document.write( " Multiply top and bottom by \"root%283%2C9%5E2%29+=+9%5E%282%2F3%29+\" \r
\n" ); document.write( "\n" ); document.write( "= \r
\n" ); document.write( "\n" ); document.write( " Simplify denominator:
\n" ); document.write( "= \"+%28%283%2Broot%283%2C3%29%29+%2A+%28root%283%2C81%29+%29%29+%2F+9++\" \r
\n" ); document.write( "\n" ); document.write( " Notice that \"+root%283%2C81%29+=+root%283%2C3%5E4%29+\"
\n" ); document.write( " Multiply out the numerator, using the above equivalence:
\n" ); document.write( "= \"+%28root%283%2C3%5E7%29+%2Broot%283%2C3%5E5%29%29++%2F+9++\" \r
\n" ); document.write( "\n" ); document.write( " Factor out a 3 from the numerator and cancel it with one of the 3's in the denominator
\n" ); document.write( " 9=3*3 so now the denominator is just 3: ( 3*Numerator / 9 = Numerator / 3 )
\n" ); document.write( "= \"+3%28root%283%2C3%5E4%29+%2Broot%283%2C3%5E2%29%29++%2F+9++\"
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "= \"+%28root%283%2C3%5E4%29+%2Broot%283%2C3%5E2%29%29++%2F+3++\"
\n" ); document.write( "
\n" ); document.write( " Expand the contents of the radical signs\r
\n" ); document.write( "\n" ); document.write( "= \"+highlight%28+%28root%283%2C81%29+%2Broot%283%2C9%29%29++%2F+3+%29+\" \r
\n" ); document.write( "\n" ); document.write( "In many cases, this is considered rationalized, and it can be left in this form.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " The only additional step I see that might be needed by your teacher would be to
\n" ); document.write( " break (A+B)/3 into A/3 + B/3 because it lowers the exponents under the radical sign:\r
\n" ); document.write( "\n" ); document.write( "Starting with
\n" ); document.write( "= \"+%28root%283%2C3%5E4%29%2F3%29+%2Broot%283%2C3%5E2%29%2F3++\" \r
\n" ); document.write( "\n" ); document.write( "= \"++root%283%2C3%29+%2B++root%283%2C9%29%2F3+\" \n" ); document.write( "
\n" );