document.write( "Question 1110939: BINOMIAL THEOREM \r
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document.write( "If 3 yards of ribbon and 2 yards of lace cost $3.37, and, at the same price, 2 yards of lace cost $1.03 more than 3 yards of ribbon, how much does it cost per yard for the ribbon and for the lace? \n" );
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Algebra.Com's Answer #725950 by ikleyn(52806)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "3R + 2L = 237 (1) (\"3 yards of ribbon and 2 yards of lace cost $3.37 = 337 cents\")\r\n" ); document.write( "2L - 3R = 103 (2) (\"2 yards of lace cost $1.03 more than 3 yards of ribbon\")\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Add the equations. You will get\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "4L = 237 + 103 = 240 ====> L = 240/4 = 60 cents.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Answer. One yard of Ribbon costs 60 cents.\r\n" ); document.write( "\r\n" ); document.write( " From this point, complete the solution on your own.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |