document.write( "Question 99712: Hi my name is Tim and I have a question about graphing triangles.\r
\n" ); document.write( "\n" ); document.write( "14. The vertices of a right triangle are (-12, 8), (24, 8), and (24, -7). Find the length of the hypotenuse of the triangle (hypotenuse = side opposite the right angle).\r
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Algebra.Com's Answer #72594 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
you have to use the distance formula: \"sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29\" on one of the sides.
\n" ); document.write( "if you put the points on graph paper it becomes obvious that 36 and 15 are the lengths of 2 of the sides. and the 3rd side is the hypotenuse.
\n" ); document.write( "now you can use the formula above or the pythagorean theorum: a^2+b^2=c^2
\n" ); document.write( "36^2+15^2=c^2
\n" ); document.write( "1296+225=1521
\n" ); document.write( "sqrt(1521)=39 (one way)
\n" ); document.write( "\"sqrt%28%28-12-24%29%5E2%2B%288%2B7%29%5E2%29\"
\n" ); document.write( "\"sqrt%28%28-36%29%5E2%2B%2815%29%5E2%29\"
\n" ); document.write( "\"sqrt%281296%2B225%29\"
\n" ); document.write( "\"sqrt%281521%29=39\" (another way)
\n" ); document.write( "Ed
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